X^2+(x-8)^2-(x+2)=2(x+9)

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Solution for X^2+(x-8)^2-(x+2)=2(x+9) equation: 



X^2+(X-8)^2-(X+2)=2(X+9)

We move all terms to the left:

X^2+(X-8)^2-(X+2)-(2(X+9))=0

We get rid of parentheses

X^2+(X-8)^2-X-(2(X+9))-2=0



We calculate terms in parentheses: -(2(X+9)), so:

2(X+9)

We multiply parentheses

2X+18

Back to the equation:

-(2X+18)



We add all the numbers together, and all the variables

X^2-1X+(X-8)^2-(2X+18)-2=0

We get rid of parentheses

X^2-1X+(X-8)^2-2X-18-2=0

We add all the numbers together, and all the variables

X^2-3X+(X-8)^2-20=0

We move all terms containing X to the left, all other terms to the right

X^2-3X+(X-8)^2=20

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